find the general solution of (y1)dx (4x y)dy = 0 then i put in standard form \\frac{dx}{dy} \\frac{4x}{1y} = \\frac{y}{y1} now im stuck i know the integrating factor is (1y)^4 which i multiply the equation with and im confused what to do next i cant really hit theAnswer to Solve the differential equation ( (4xy^2 y))\,dx ((4x^2y x ))\,dy = 0 By signing up, you'll get thousands of stepbystepThe differential equation corresponding to the equation y 2 = a ( b − x 2) where a, b are constants is J & K CET 13 7 If x y = A s i n x B c o s x is the solution of the differential equation x d 2 y d x 2 − 5 a d y d x x y = 0 then the value of a is equal to KEAM 13 8
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Y(4x+y)dx-2(x^2-y)dy=0
Y(4x+y)dx-2(x^2-y)dy=0-$M~dx N~dy = 0$ $y(4x y)~dx 2(x^2 y)~dy = 0$ $M = y(4x y) = 4xy y^2$ $N = 2(x^2 y) = 2x^2 2y$ $\dfrac{\partial M}{\partial y} = 4x 2y$Learn how to solve differential equations problems step by step online Solve the differential equation (y^2e^(xy^2)4x^3)dx(2x*y*e^(xy^2)3y^2)dy=0
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history 可以尝试用全微分方程求解，过程如下： d (x^3/3xyy^2/2)= (x^2y)dx (xy)dy=0 所以,通解为： x^3/3xyy^2/2=C 这种题目的技巧是，多做题，熟练了就可以看得出来了。 有一阶微分方程的形式y'P (x)y=Q (x),直接套用定理公式。 追问 d（xy）就能得到 xdy＋ydx？ 追答Answer to 1 Find general solution for the differential equation dy/dx 2xy = 4x 2 Find particular solution subject to given initial
Simple and best practice solution for (4xxy^2)dx(yx^2y)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itV 5 dx 2v2 A dv30 dx 2v2 5v B ВI think it's reasonable to do one more separable differential equation from so let's do it derivative of Y with respect to X is equal to Y cosine of X divided by 1 plus 2y squared and they give us an initial condition that Y of 0 is equal to 1 or when X is equal to 0 Y is equal to 1 and I know we did a couple already but another way to think about separable differential equations is really all
(y^22xy)dx (x^2) dy = 0 Integrating factor y^2 solution xx^2/y = C Finding the integrating factor Giving these things some names names M(x,y) = y^22xy N(x,y) = x^2 M(x,y) dx N(x,y) = 0 We're looking to make this an exact equation, because if we do, it can be solved rather systematically In order to be exact, by claurait's theoem (think that's the name ofEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (2x^2y)dx(x^2yx)dy=0 so that you understand better Ex 96, 11 For each of the differential equation find the general solution 𝑦 𝑑𝑥 𝑥− 𝑦2𝑑𝑦=0 Step 1 Put in form 𝑑𝑦𝑑𝑥 Py = Q or 𝑑𝑥𝑑𝑦 P1 x = Q1, y dx (x − y2) dy = 0 y dx = − (x − y2)dy 𝑑𝑦𝑑𝑥 = −𝑦𝑥− 𝑦2 This is not of the form 𝑑𝑦𝑑𝑥 Py = Q ∴ we find
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1216 Предлагаем онлайн консультации специалистов в различных областях юриспруденция, психология, бизнес, эзотерика, астрология, гадания Самая большая база специалистов в Рунете Общение с экспертами в чате, поSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more55 Q1 (2xy sin x)dx (x cos y)dy= 0 Q2 (1 2x/ y2) dx 2y x2 y2dy = 0 Q3 Q4 2xy 9x2 (2y x1)=0;
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Homework Statement Solve 6x^2*y^2*dx4x^3*y*dy=0 Homework Equations This is an exact equation The Attempt at a Solution Here's my work 6x^2*y^2*dx=4x^3*y*dy 1/x dx=2/3*1/y*dy ln abs(x)C=2/3*ln abs(y) 1/y^(2/3)=Cx y^(2/3)=1/(Cx) xy^(2/3)=1/C C=1/(xy^(2/3)) But the answer in the bookAnswer to Solve each differential equation x dy y^2 dx = 0 3x^3 y^2 dx xy dy \= 0 x dy ydx = 0 sec x dy csc y dx = 0 dy/dVerify implicit solution 2xydx(x^2y)dy=0;
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Solve y(4xy)dx 2(x^2y)dy = 0 by finding the integrating factor and test for exactness Expert Answer Previous question Next question Get more help from Chegg Solve it with our calculus problem solver and calculatorSolution for Consider (x y)(4x y) dx x(5x y) dy=0 Let y= VX Then the resulting differential equation is?Equations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (x^33xy^2)dx(3x^2yy^3)dy=0 so that you understand better
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Solution for For the equation, 2y(x^2 y x)dx (x^2 2y)dy = 0, what is dM/dy dN/dx?(2x y 3) dx (4x 2y 7) dy = 0 iya betul kita turunkan satu satu ya * (2x y 3) dx 2x dx = 2 y dx = 0 3 dx = 0 maka (2x y 3) dx = 2 * (4x 2y 7) dy 4x dy = 0 2y dy = 2 7 dy = 0 maka (4x 2y 7) dy = 2 jadi (2x y 3) dx (The equation is M(x,y)dx N(x,y)dy =0 with M = 4xy y^2 , M_y = 4x 2y N = 2y 2x^2 , N_x = 4x # M_y The equation is not exact , but (N_x M_y)/M = 2/y , depends only on y The integrating factor is 1/y^2 and leads to the equation P(x,y
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